arrays - Switching Matrix columns and rows in C++ -

i have 6 x 6 matrix, , storing values in 1 dimensional array of size 36. want rearrange rows columns , columns rows. method trying copy values array, sorted properly. trying loop:

    (int = 0; < 6; ++i){         copyarray[i]= array[i*6];     } 

this works fine first new row made of first column, how continue of them? have tried nested loops cannot come proper algorithm using iterators. manually, have done code.

i coding in c++, if can in similar language fine. feel math problem.

the question: how solve switching out rows , columns? (example: if denoting first rows , columns 0, in 6x6 matrix, both rows , columns go 0 5. therefore, switching rows , columns, value in row 2, column 5 switched value in row 5, column 2.)

couldn't use nested for loop , this?

for (int = 0; < 6; ++i)     (int j = 0; j < 6; ++j)         copyarray[i*6+j]= array[j*6+i]; 

here's test program can run show works:

#include <stdio.h>  int main() {     int array[36] = {1,1,1,1,1,1,                      2,2,2,2,2,2,                      3,3,3,3,3,3,                      4,4,4,4,4,4,                      5,5,5,5,5,5,                      6,6,6,6,6,6};     int copyarray[36];      (int = 0; < 6; ++i)         (int j = 0; j < 6; ++j)             copyarray[i*6+j]= array[j*6+i];      (int = 0; < 36; ++i)     {         if (i % 6 == 0)             printf("\n");          printf("%d ", array[i]);      }      printf("\n");     printf("\n");      (int = 0; < 36; ++i)     {         if (i % 6 == 0)             printf("\n");          printf("%d ", copyarray[i]);     }      return 0; } 

output:

1 1 1 1 1 1  2 2 2 2 2 2  3 3 3 3 3 3  4 4 4 4 4 4  5 5 5 5 5 5  6 6 6 6 6 6    1 2 3 4 5 6  1 2 3 4 5 6  1 2 3 4 5 6  1 2 3 4 5 6  1 2 3 4 5 6  1 2 3 4 5 6