c - How to compare number against an interval? ( x > (1,10)) -

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how compare 1 number against interval.

is there way shorten expression:

if ((x%10) == 1 || (x%10) == 2 ||  (x%10) == 3 || (x%10) == 4 ) // ... till number 9.

assuming x integer, there 10 possible values. , 1 not checked, 0, false integer.

if (x % 10) {    ...

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