list - Haskell recursion odd -

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i have define own predicate function recursively searches list of numbers , returns true if finds odd number, false otherwise.

i have set x = [1..100] test data need show. however, bit unsure how recursion search list. i'm not looking definitive answer explanation on how recursion go around searching in list.

what want function any odd:

any :: (a -> bool) -> [a] -> bool  odd :: integral => -> bool  odd :: integral => [a] -> bool  anyodd :: integral => [a] -> bool anyodd = odd

if want define anyodd function have use recursion:

anyodd :: integral => [a] -> bool anyodd []       = undefined anyodd (x:xs)     | odd x     = undefined     | otherwise = undefined

you need replace undefined actual logic.


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