coordinates - Find the x and y of a case in a maze ( in C) -

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i want find distance between case(n) , case(m), n!=m how can find x0, x1, y0 , y1 using case number, height , width in maze ? there formule ?

float distance(maze* maze, int start, int end) {   float x0 = ..??..     float x1 = ..??..    float y0 = ..??..    float y1 = ..??..    float dx = x0 - x1;   float dy = y0 - y1;    return sqrtf(dx*dx+dy*dy); }

example of maze :

<----------- width ------------->    case0 | case1 | case2  | case3  |  case4 | case5 | case6  | case7  |     height    case8 | case9 | case10 | case11 |

first calculate indexes:

int x0 = m % width; // % = modulo operation int y0 = m / width;  int x1 = n % width; int y1 = n / width;  int dx = x1 - x0; int dy = y1 - y0;  return sqrtf(dx*dx + dy*dy);

make sure perform index calculations int. int-division truncates decimals. modulo operation returns remainder of division. x % width yields value in range 0 .. width-1.


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