c - using function to print two variables -

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the function seems not work, correct form when print variable(string) in function?

void f1(char ara, char arb) {     printf("acronym found:\n       %s - %s\n", ara, arb);  }   int main(void) {     char  arc[20],ar1[] = "afaik",ard1[] = "as far know";  printf("welcome internet system\nenter \"quit\" exit program\n"); {     printf("enter string: ");     scanf("%s", &arc);      if (strcmp(arc, ar1) == 0)         f1(ar1, ard1);  .......

just change type of arguments in f1 pointer variable.

void f1(char *ara, char *arb)

because while giving char take 1 character has 1 byte store character.

when convert character pointer, have 4 bytes store string.


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