r - Adding to a numeric matrix with data from a dataframe -

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i'm wondering if missing faster way of doing following, other doing laborious loop.

say have matrix this:

m1 <- structure(c(0, 2, 2, 1, 0, 1, 1, 1, 0), .dim = c(3l, 3l), .dimnames = list(     c("ak", "jw", "sz"), c("ak", "jw", "sz")))  #m1 #    ak jw sz # ak  0  1  1 # jw  2  0  1 # sz  2  1  0

now, want add values following dataframe. here can see individuals listed in 'id1' , 'id2' , value add in 'val'. 

dfx <- structure(list(id1 = c("jw", "sz", "sz"), id2 = c("ak", "ak",  "jw"), val = c(1.5, 2.5, 1)), .names = c("id1", "id2", "val"), row.names = c(na,  -3l), class = "data.frame")  #dfx #  id1 id2 val #1  jw  ak 1.5 #2  sz  ak 2.5 #3  sz  jw 1.0

each value should added respective cell of matrix e.g 2.5 should added m1[sz, ak]. however, same value should added transposed cell, i.e. 2.5 should added m1[ak, sz].

the resulting matrix should like:

#    ak  jw  sz #ak 0.0 2.5 3.5 #jw 3.5 0.0 2.0 #sz 4.5 2.0 0.0

this can achieved instance creating loop every row of 'dfx':

m1[rownames(m1)=="jw",rownames(m1)=="ak"] <- m1[rownames(m1)=="jw",rownames(m1)=="ak"] + 1.5 m1[rownames(m1)=="ak",rownames(m1)=="jw"] <- m1[rownames(m1)=="ak",rownames(m1)=="jw"] + 1.5

any ideas/pointers better way appreciated:

a possible base alternative data frame reshaped same dimensions matrix. achieved first converting 'id1' , 'id2' factors levels picked 'm1'. xtabs used reshaping. result , transpose added 'm1'.

dfx[ , c("id1", "id2")] <- lapply(dfx[ , c("id1", "id2")], function(x) factor(x, levels = rownames(m1))) m2 <- xtabs(val ~ ., data = dfx) m1 + m2 + t(m2)  #     ak  jw  sz # ak 0.0 2.5 3.5 # jw 3.5 0.0 2.0 # sz 4.5 2.0 0.0

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