Java: BitSet comparison -

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suppose have 2 bitset objects in java values as

//<msb....lsb> b1:<11000101> b2:<10111101>

how can compare b1 , b2 know value represented b1 greater b2.

are logical operators (>,<,==) overloaded bitset? or have write own implementation?

update: found "the operator > undefined argument type(s) java.util.bitset, java.util.bitset". there built-in way so?

you can xor-ing 2 sets together, , comparing length of result lengths of bit sets:

  • if xor empty, bit sets equal. can bypass operation calling equals()
  • otherwise, length of xor result equal position of significant bit different between 2 values.
  • whichever of 2 operands has bit set greater 1 of two.

here sample implementation:

int compare(bitset lhs, bitset rhs) {     if (lhs.equals(rhs)) return 0;     bitset xor = (bitset)lhs.clone();     xor.xor(rhs);     int firstdifferent = xor.length()-1;     if(firstdifferent==-1)             return 0;      return rhs.get(firstdifferent) ? 1 : -1; }

demo.


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