php - Notice: Undefined variable in function += -
this question has answer here:
- reference - error mean in php? 30 answers
in couple scripts i've created same error when connect on wampserver.
every thing running smooth don't errors. notice: undefined variable
the $watdan
function giving me error.
for example i've amounts need count up: 2835 + 11024
i've multipled those. when use code:
$total[0] = $totaal->amount; $total[1] = $totaal->price; $watdan += $total[0] * $total[1];
im getting right answer 13859
i'm getting error i've mentioned.
now when add $watdan=0;
11024
without given error.
this full code:
$pak14 = $db->query("select * log_drops inner join log_items on log_drops.item = log_items.name , log_drops.game = log_items.game log_drops.log_id = '".$id."' order log_drops.log_name asc") or die($db->error); while($totaal = $pak14->fetch_object()) { $total[0] = $totaal->amount; $total[1] = $totaal->price; $watdan += $total[0] * $total[1]; } if(isset($watdan)) { echo $watdan; echo ' gold'; }
not declare variable $watdan
. declare variable 0
or ''
after use it.
$watdan=0;//add in code $total[0] = $totaal->amount; $total[1] = $totaal->price; $watdan += $total[0] * $total[1];
check
$pak14 = $db->query("select * log_drops inner join log_items on log_drops.item = log_items.name , log_drops.game = log_items.game log_drops.log_id = '".$id."' order log_drops.log_name asc") or die($db->error); $watdan=0;//add in code while($totaal = $pak14->fetch_object()) { $total[0] = $totaal->amount; $total[1] = $totaal->price; $watdan += $total[0] * $total[1]; } if(isset($watdan)) { echo $watdan; echo ' gold'; }
Comments
Post a Comment