bash - How can I subtract timestamp results from `date` in one line of shell? -

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i can generate 2 timestamps so:

date +"%s" -d "$(curl -s --head http://google.com | grep ^date: | sed 's/date: //g')" // result: 1417800327  date +"%s" // result: 1417800325

how can subtract them 1 line?

echo "$((1417800327-1417800325))" // result: 2

but want closer to:

echo "$(( (date +"%s" -d "$(curl -s --head http://google.com | grep ^date: | sed 's/date: //g')") - (date +"%s")))"

try doing :

lang=c echo $(( $(date +%s) - $(date -d "$(curl -s --head http://google.com 2>&1 | awk -f'date: ' '/^date:/{print $2}')" +%s) ))

or splitted multi-lines readability :

lang=c echo $((     $(date +%s) - $(         date -d "$(curl -s --head http://google.com |             awk -f'date: ' '/^date:/{print $2}'     )" +%s) ))

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