c - Read strings from console -

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• how read string keyboard using c? getting segmentation fault passing in char * 5 answers

i wanna write program array of pointers char store strings read console in it. string determined \n. ideas how can this?

code mix of pseudocode far:

char** arr;  arr = malloc(sizeof(char*) * 5); arr = malloc(sizeof(char) * 10);  while (no \n read) {     // store string in array } 

i have no clue how this.

#include <stdio.h> #include <stdlib.h>  int main(){     int i;     char **arr;     arr = malloc(sizeof(char*) * 5);//for 5 string      for(i=0;i<5;++i){         arr[i] = malloc(sizeof(char) * 10);//reserved storage space length 9         scanf("%9[^\n]%*c", arr[i]);//read until \n, , discard \n     }     printf("\n");     //check print , free     for(i=0;i<5;++i){         puts(arr[i]);         free(arr[i]);     }     free(arr);     return 0; } 

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int i, n; char **arr; arr = malloc(sizeof(char*) * 5);  for(i=0;i<5;++i){     arr[i] = malloc(sizeof(char) * 10); } i=0; while(i<5 && 1==scanf("%9[^\n]%*c", arr[i]))     ++i; n = i; printf("\n"); //check print for(i=0;i<n;++i){     puts(arr[i]); } //deallocate for(i=0;i<5;++i)     free(arr[i]); free(arr);